The safari park tickets are priced at $11 and $5. The number of $11-dollar tickets available is 1
15 that of the number of $5-dollar tickets. 3 out of 7 of the $11-dollar tickets and all the $5-dollar tickets were sold. The ticket sales amounted to $3357. How much more would have been collected if all the tickets were sold?
|
$11 |
$5 |
Comparing $11 and $5 tickets at first |
6x7 = 42 u |
5x7 = 35 u |
Before |
7x6 = 42 u |
|
Change |
- 3x6 = - 18 u |
- 35 u |
After |
4x6 = 24 u |
0 u |
The number of 11 tickets at first is repeated. Make the number of 11 tickets the same. LCM of 7 and 6 is 42.
1
15 =
65 Number of $11 tickets : $5 tickets = 6 : 5
|
$11 |
$5 |
Total |
Number |
18 u |
35 u |
|
Value |
$11 |
$5 |
|
Total value |
198 u |
175 u |
$3357 |
Total amount collected from the sale of the sold tickets
= 198 u + 175 u
= 373 u
1 u = 3357 ÷ 373 = 9
Number of $11-tickets left unsold
= 24 u
= 24 x 9
= 216
More amount to be collected if all the tickets were sold
= 216 x 11
= $2376
Answer(s): $2376