The safari park tickets are priced at $21 and $15. The number of $21-dollar tickets available is 1
35 that of the number of $15-dollar tickets. 2 out of 3 of the $21-dollar tickets and all the $15-dollar tickets were sold. The ticket sales amounted to $1683. How much more would have been collected if all the tickets were sold?
|
$21 |
$15 |
Comparing $21 and $15 tickets at first |
8x3 = 24 u |
5x3 = 15 u |
Before |
3x8 = 24 u |
|
Change |
- 2x8 = - 16 u |
- 15 u |
After |
1x8 = 8 u |
0 u |
The number of 21 tickets at first is repeated. Make the number of 21 tickets the same. LCM of 3 and 8 is 24.
1
35 =
85 Number of $21 tickets : $15 tickets = 8 : 5
|
$21 |
$15 |
Total |
Number |
16 u |
15 u |
|
Value |
$21 |
$15 |
|
Total value |
336 u |
225 u |
$1683 |
Total amount collected from the sale of the sold tickets
= 336 u + 225 u
= 561 u
1 u = 1683 ÷ 561 = 3
Number of $21-tickets left unsold
= 8 u
= 8 x 3
= 24
More amount to be collected if all the tickets were sold
= 24 x 21
= $504
Answer(s): $504