The tourist attraction tickets are priced at $17 and $7. The number of $17-dollar tickets available is 1
15 that of the number of $7-dollar tickets. 3 out of 7 of the $17-dollar tickets and all the $7-dollar tickets were sold. The ticket sales amounted to $4959. How much more would have been collected if all the tickets were sold?
|
$17 |
$7 |
Comparing $17 and $7 tickets at first |
6x7 = 42 u |
5x7 = 35 u |
Before |
7x6 = 42 u |
|
Change |
- 3x6 = - 18 u |
- 35 u |
After |
4x6 = 24 u |
0 u |
The number of 17 tickets at first is repeated. Make the number of 17 tickets the same. LCM of 7 and 6 is 42.
1
15 =
65 Number of $17 tickets : $7 tickets = 6 : 5
|
$17 |
$7 |
Total |
Number |
18 u |
35 u |
|
Value |
$17 |
$7 |
|
Total value |
306 u |
245 u |
$4959 |
Total amount collected from the sale of the sold tickets
= 306 u + 245 u
= 551 u
1 u = 4959 ÷ 551 = 9
Number of $17-tickets left unsold
= 24 u
= 24 x 9
= 216
More amount to be collected if all the tickets were sold
= 216 x 17
= $3672
Answer(s): $3672