The stadium tickets are priced at $29 and $20.  The number of $29-dollar tickets available is  1⁵₆ that of the number of $20-dollar tickets. 2 out of 3 of the $29-dollar tickets and all the $20-dollar tickets were sold. The ticket sales amounted to $7984. How much more would have been collected if all the tickets were sold?

	$29	$20
Comparing $29 and $20 tickets at first	11x3 = 33 u	6x3 = 18 u
Before	3x11 = 33 u
Change	- 2x11 = - 22 u	- 18 u
After	1x11 = 11 u	0 u

The number of 29 tickets at first is repeated.  Make the number of 29 tickets the same.  LCM of 3 and 11 is 33.

1⁵₆ = ¹¹₆

Number of $29 tickets : $20 tickets = 11 : 6

	$29	$20	Total
Number	22 u	18 u
Value	$29	$20
Total value	638 u	360 u	$7984

Total amount collected from the sale of the sold tickets
= 638 u + 360 u
= 998 u

1 u = 7984 ÷ 998 = 8

Number of $29-tickets left unsold
= 11 u 
= 11 x 8
= 88

More amount to be collected if all the tickets were sold
= 88 x 29
= $2552

Answer(s): $2552