The park tickets are priced at $10 and $5.  The number of $10-dollar tickets available is  1¹₂ that of the number of $5-dollar tickets. 3 out of 7 of the $10-dollar tickets and all the $5-dollar tickets were sold. The ticket sales amounted to $480. How much more would have been collected if all the tickets were sold?

	$10	$5
Comparing $10 and $5 tickets at first	3x7 = 21 u	2x7 = 14 u
Before	7x3 = 21 u
Change	- 3x3 = - 9 u	- 14 u
After	4x3 = 12 u	0 u

The number of 10 tickets at first is repeated.  Make the number of 10 tickets the same.  LCM of 7 and 3 is 21.

1¹₂ = ³₂

Number of $10 tickets : $5 tickets = 3 : 2

	$10	$5	Total
Number	9 u	14 u
Value	$10	$5
Total value	90 u	70 u	$480

Total amount collected from the sale of the sold tickets
= 90 u + 70 u
= 160 u

1 u = 480 ÷ 160 = 3

Number of $10-tickets left unsold
= 12 u 
= 12 x 3
= 36

More amount to be collected if all the tickets were sold
= 36 x 10
= $360

Answer(s): $360