The stadium tickets are priced at $20 and $10. The number of $20-dollar tickets available is 2
15 that of the number of $10-dollar tickets. 2 out of 3 of the $20-dollar tickets and all the $10-dollar tickets were sold. The ticket sales amounted to $5900. How much more would have been collected if all the tickets were sold?
|
$20 |
$10 |
Comparing $20 and $10 tickets at first |
11x3 = 33 u |
5x3 = 15 u |
Before |
3x11 = 33 u |
|
Change |
- 2x11 = - 22 u |
- 15 u |
After |
1x11 = 11 u |
0 u |
The number of 20 tickets at first is repeated. Make the number of 20 tickets the same. LCM of 3 and 11 is 33.
2
15 =
115 Number of $20 tickets : $10 tickets = 11 : 5
|
$20 |
$10 |
Total |
Number |
22 u |
15 u |
|
Value |
$20 |
$10 |
|
Total value |
440 u |
150 u |
$5900 |
Total amount collected from the sale of the sold tickets
= 440 u + 150 u
= 590 u
1 u = 5900 ÷ 590 = 10
Number of $20-tickets left unsold
= 11 u
= 11 x 10
= 110
More amount to be collected if all the tickets were sold
= 110 x 20
= $2200
Answer(s): $2200