The tourist attraction tickets are priced at $14 and $10. The number of $14-dollar tickets available is 1
13 that of the number of $10-dollar tickets. 3 out of 5 of the $14-dollar tickets and all the $10-dollar tickets were sold. The ticket sales amounted to $1272. How much more would have been collected if all the tickets were sold?
|
$14 |
$10 |
Comparing $14 and $10 tickets at first |
4x5 = 20 u |
3x5 = 15 u |
Before |
5x4 = 20 u |
|
Change |
- 3x4 = - 12 u |
- 15 u |
After |
2x4 = 8 u |
0 u |
The number of 14 tickets at first is repeated. Make the number of 14 tickets the same. LCM of 5 and 4 is 20.
1
13 =
43 Number of $14 tickets : $10 tickets = 4 : 3
|
$14 |
$10 |
Total |
Number |
12 u |
15 u |
|
Value |
$14 |
$10 |
|
Total value |
168 u |
150 u |
$1272 |
Total amount collected from the sale of the sold tickets
= 168 u + 150 u
= 318 u
1 u = 1272 ÷ 318 = 4
Number of $14-tickets left unsold
= 8 u
= 8 x 4
= 32
More amount to be collected if all the tickets were sold
= 32 x 14
= $448
Answer(s): $448