The tourist attraction tickets are priced at $19 and $13. The number of $19-dollar tickets available is 2
12 that of the number of $13-dollar tickets. 3 out of 4 of the $19-dollar tickets and all the $13-dollar tickets were sold. The ticket sales amounted to $3501. How much more would have been collected if all the tickets were sold?
|
$19 |
$13 |
Comparing $19 and $13 tickets at first |
5x4 = 20 u |
2x4 = 8 u |
Before |
4x5 = 20 u |
|
Change |
- 3x5 = - 15 u |
- 8 u |
After |
1x5 = 5 u |
0 u |
The number of 19 tickets at first is repeated. Make the number of 19 tickets the same. LCM of 4 and 5 is 20.
2
12 =
52 Number of $19 tickets : $13 tickets = 5 : 2
|
$19 |
$13 |
Total |
Number |
15 u |
8 u |
|
Value |
$19 |
$13 |
|
Total value |
285 u |
104 u |
$3501 |
Total amount collected from the sale of the sold tickets
= 285 u + 104 u
= 389 u
1 u = 3501 ÷ 389 = 9
Number of $19-tickets left unsold
= 5 u
= 5 x 9
= 45
More amount to be collected if all the tickets were sold
= 45 x 19
= $855
Answer(s): $855