The tourist attraction tickets are priced at $16 and $12. The number of $16-dollar tickets available is 1
34 that of the number of $12-dollar tickets. 3 out of 5 of the $16-dollar tickets and all the $12-dollar tickets were sold. The ticket sales amounted to $2880. How much more would have been collected if all the tickets were sold?
|
$16 |
$12 |
Comparing $16 and $12 tickets at first |
7x5 = 35 u |
4x5 = 20 u |
Before |
5x7 = 35 u |
|
Change |
- 3x7 = - 21 u |
- 20 u |
After |
2x7 = 14 u |
0 u |
The number of 16 tickets at first is repeated. Make the number of 16 tickets the same. LCM of 5 and 7 is 35.
1
34 =
74 Number of $16 tickets : $12 tickets = 7 : 4
|
$16 |
$12 |
Total |
Number |
21 u |
20 u |
|
Value |
$16 |
$12 |
|
Total value |
336 u |
240 u |
$2880 |
Total amount collected from the sale of the sold tickets
= 336 u + 240 u
= 576 u
1 u = 2880 ÷ 576 = 5
Number of $16-tickets left unsold
= 14 u
= 14 x 5
= 70
More amount to be collected if all the tickets were sold
= 70 x 16
= $1120
Answer(s): $1120