The museum tickets are priced at $9 and $7. The number of $9-dollar tickets available is 2
15 that of the number of $7-dollar tickets. 3 out of 7 of the $9-dollar tickets and all the $7-dollar tickets were sold. The ticket sales amounted to $3252. How much more would have been collected if all the tickets were sold?
|
$9 |
$7 |
Comparing $9 and $7 tickets at first |
11x7 = 77 u |
5x7 = 35 u |
Before |
7x11 = 77 u |
|
Change |
- 3x11 = - 33 u |
- 35 u |
After |
4x11 = 44 u |
0 u |
The number of 9 tickets at first is repeated. Make the number of 9 tickets the same. LCM of 7 and 11 is 77.
2
15 =
115 Number of $9 tickets : $7 tickets = 11 : 5
|
$9 |
$7 |
Total |
Number |
33 u |
35 u |
|
Value |
$9 |
$7 |
|
Total value |
297 u |
245 u |
$3252 |
Total amount collected from the sale of the sold tickets
= 297 u + 245 u
= 542 u
1 u = 3252 ÷ 542 = 6
Number of $9-tickets left unsold
= 44 u
= 44 x 6
= 264
More amount to be collected if all the tickets were sold
= 264 x 9
= $2376
Answer(s): $2376