The tourist attraction tickets are priced at $26 and $18. The number of $26-dollar tickets available is 1
12 that of the number of $18-dollar tickets. 2 out of 5 of the $26-dollar tickets and all the $18-dollar tickets were sold. The ticket sales amounted to $672. How much more would have been collected if all the tickets were sold?
|
$26 |
$18 |
Comparing $26 and $18 tickets at first |
3x5 = 15 u |
2x5 = 10 u |
Before |
5x3 = 15 u |
|
Change |
- 2x3 = - 6 u |
- 10 u |
After |
3x3 = 9 u |
0 u |
The number of 26 tickets at first is repeated. Make the number of 26 tickets the same. LCM of 5 and 3 is 15.
1
12 =
32 Number of $26 tickets : $18 tickets = 3 : 2
|
$26 |
$18 |
Total |
Number |
6 u |
10 u |
|
Value |
$26 |
$18 |
|
Total value |
156 u |
180 u |
$672 |
Total amount collected from the sale of the sold tickets
= 156 u + 180 u
= 336 u
1 u = 672 ÷ 336 = 2
Number of $26-tickets left unsold
= 9 u
= 9 x 2
= 18
More amount to be collected if all the tickets were sold
= 18 x 26
= $468
Answer(s): $468