The museum tickets are priced at $26 and $20.  The number of $26-dollar tickets available is  1²₅ that of the number of $20-dollar tickets. 3 out of 5 of the $26-dollar tickets and all the $20-dollar tickets were sold. The ticket sales amounted to $8368. How much more would have been collected if all the tickets were sold?

	$26	$20
Comparing $26 and $20 tickets at first	7x5 = 35 u	5x5 = 25 u
Before	5x7 = 35 u
Change	- 3x7 = - 21 u	- 25 u
After	2x7 = 14 u	0 u

The number of 26 tickets at first is repeated.  Make the number of 26 tickets the same.  LCM of 5 and 7 is 35.

1²₅ = ⁷₅

Number of $26 tickets : $20 tickets = 7 : 5

	$26	$20	Total
Number	21 u	25 u
Value	$26	$20
Total value	546 u	500 u	$8368

Total amount collected from the sale of the sold tickets
= 546 u + 500 u
= 1046 u

1 u = 8368 ÷ 1046 = 8

Number of $26-tickets left unsold
= 14 u 
= 14 x 8
= 112

More amount to be collected if all the tickets were sold
= 112 x 26
= $2912

Answer(s): $2912