The tourist attraction tickets are priced at $26 and $18.  The number of $26-dollar tickets available is  1⁴₅ that of the number of $18-dollar tickets. 2 out of 5 of the $26-dollar tickets and all the $18-dollar tickets were sold. The ticket sales amounted to $11016. How much more would have been collected if all the tickets were sold?

	$26	$18
Comparing $26 and $18 tickets at first	9x5 = 45 u	5x5 = 25 u
Before	5x9 = 45 u
Change	- 2x9 = - 18 u	- 25 u
After	3x9 = 27 u	0 u

The number of 26 tickets at first is repeated.  Make the number of 26 tickets the same.  LCM of 5 and 9 is 45.

1⁴₅ = ⁹₅

Number of $26 tickets : $18 tickets = 9 : 5

	$26	$18	Total
Number	18 u	25 u
Value	$26	$18
Total value	468 u	450 u	$11016

Total amount collected from the sale of the sold tickets
= 468 u + 450 u
= 918 u

1 u = 11016 ÷ 918 = 12

Number of $26-tickets left unsold
= 27 u 
= 27 x 12
= 324

More amount to be collected if all the tickets were sold
= 324 x 26
= $8424

Answer(s): $8424