The park tickets are priced at $20 and $11.  The number of $20-dollar tickets available is  2¹₂ that of the number of $11-dollar tickets. 3 out of 7 of the $20-dollar tickets and all the $11-dollar tickets were sold. The ticket sales amounted to $1362. How much more would have been collected if all the tickets were sold?

	$20	$11
Comparing $20 and $11 tickets at first	5x7 = 35 u	2x7 = 14 u
Before	7x5 = 35 u
Change	- 3x5 = - 15 u	- 14 u
After	4x5 = 20 u	0 u

The number of 20 tickets at first is repeated.  Make the number of 20 tickets the same.  LCM of 7 and 5 is 35.

2¹₂ = ⁵₂

Number of $20 tickets : $11 tickets = 5 : 2

	$20	$11	Total
Number	15 u	14 u
Value	$20	$11
Total value	300 u	154 u	$1362

Total amount collected from the sale of the sold tickets
= 300 u + 154 u
= 454 u

1 u = 1362 ÷ 454 = 3

Number of $20-tickets left unsold
= 20 u 
= 20 x 3
= 60

More amount to be collected if all the tickets were sold
= 60 x 20
= $1200

Answer(s): $1200