The tourist attraction tickets are priced at $9 and $5.  The number of $9-dollar tickets available is  1⁵₆ that of the number of $5-dollar tickets. 2 out of 3 of the $9-dollar tickets and all the $5-dollar tickets were sold. The ticket sales amounted to $2304. How much more would have been collected if all the tickets were sold?

	$9	$5
Comparing $9 and $5 tickets at first	11x3 = 33 u	6x3 = 18 u
Before	3x11 = 33 u
Change	- 2x11 = - 22 u	- 18 u
After	1x11 = 11 u	0 u

The number of 9 tickets at first is repeated.  Make the number of 9 tickets the same.  LCM of 3 and 11 is 33.

1⁵₆ = ¹¹₆

Number of $9 tickets : $5 tickets = 11 : 6

	$9	$5	Total
Number	22 u	18 u
Value	$9	$5
Total value	198 u	90 u	$2304

Total amount collected from the sale of the sold tickets
= 198 u + 90 u
= 288 u

1 u = 2304 ÷ 288 = 8

Number of $9-tickets left unsold
= 11 u 
= 11 x 8
= 88

More amount to be collected if all the tickets were sold
= 88 x 9
= $792

Answer(s): $792