The park tickets are priced at $20 and $15. The number of $20-dollar tickets available is 1
23 that of the number of $15-dollar tickets. 3 out of 7 of the $20-dollar tickets and all the $15-dollar tickets were sold. The ticket sales amounted to $4305. How much more would have been collected if all the tickets were sold?
|
$20 |
$15 |
Comparing $20 and $15 tickets at first |
5x7 = 35 u |
3x7 = 21 u |
Before |
7x5 = 35 u |
|
Change |
- 3x5 = - 15 u |
- 21 u |
After |
4x5 = 20 u |
0 u |
The number of 20 tickets at first is repeated. Make the number of 20 tickets the same. LCM of 7 and 5 is 35.
1
23 =
53 Number of $20 tickets : $15 tickets = 5 : 3
|
$20 |
$15 |
Total |
Number |
15 u |
21 u |
|
Value |
$20 |
$15 |
|
Total value |
300 u |
315 u |
$4305 |
Total amount collected from the sale of the sold tickets
= 300 u + 315 u
= 615 u
1 u = 4305 ÷ 615 = 7
Number of $20-tickets left unsold
= 20 u
= 20 x 7
= 140
More amount to be collected if all the tickets were sold
= 140 x 20
= $2800
Answer(s): $2800