The museum tickets are priced at $16 and $7. The number of $16-dollar tickets available is 1
56 that of the number of $7-dollar tickets. 2 out of 3 of the $16-dollar tickets and all the $7-dollar tickets were sold. The ticket sales amounted to $3824. How much more would have been collected if all the tickets were sold?
|
$16 |
$7 |
Comparing $16 and $7 tickets at first |
11x3 = 33 u |
6x3 = 18 u |
Before |
3x11 = 33 u |
|
Change |
- 2x11 = - 22 u |
- 18 u |
After |
1x11 = 11 u |
0 u |
The number of 16 tickets at first is repeated. Make the number of 16 tickets the same. LCM of 3 and 11 is 33.
1
56 =
116 Number of $16 tickets : $7 tickets = 11 : 6
|
$16 |
$7 |
Total |
Number |
22 u |
18 u |
|
Value |
$16 |
$7 |
|
Total value |
352 u |
126 u |
$3824 |
Total amount collected from the sale of the sold tickets
= 352 u + 126 u
= 478 u
1 u = 3824 ÷ 478 = 8
Number of $16-tickets left unsold
= 11 u
= 11 x 8
= 88
More amount to be collected if all the tickets were sold
= 88 x 16
= $1408
Answer(s): $1408