The museum tickets are priced at $20 and $16. The number of $20-dollar tickets available is 2
35 that of the number of $16-dollar tickets. 2 out of 3 of the $20-dollar tickets and all the $16-dollar tickets were sold. The ticket sales amounted to $6080. How much more would have been collected if all the tickets were sold?
|
$20 |
$16 |
Comparing $20 and $16 tickets at first |
13x3 = 39 u |
5x3 = 15 u |
Before |
3x13 = 39 u |
|
Change |
- 2x13 = - 26 u |
- 15 u |
After |
1x13 = 13 u |
0 u |
The number of 20 tickets at first is repeated. Make the number of 20 tickets the same. LCM of 3 and 13 is 39.
2
35 =
135 Number of $20 tickets : $16 tickets = 13 : 5
|
$20 |
$16 |
Total |
Number |
26 u |
15 u |
|
Value |
$20 |
$16 |
|
Total value |
520 u |
240 u |
$6080 |
Total amount collected from the sale of the sold tickets
= 520 u + 240 u
= 760 u
1 u = 6080 ÷ 760 = 8
Number of $20-tickets left unsold
= 13 u
= 13 x 8
= 104
More amount to be collected if all the tickets were sold
= 104 x 20
= $2080
Answer(s): $2080