The safari park tickets are priced at $22 and $18. The number of $22-dollar tickets available is 1
12 that of the number of $18-dollar tickets. 3 out of 4 of the $22-dollar tickets and all the $18-dollar tickets were sold. The ticket sales amounted to $2052. How much more would have been collected if all the tickets were sold?
|
$22 |
$18 |
Comparing $22 and $18 tickets at first |
3x4 = 12 u |
2x4 = 8 u |
Before |
4x3 = 12 u |
|
Change |
- 3x3 = - 9 u |
- 8 u |
After |
1x3 = 3 u |
0 u |
The number of 22 tickets at first is repeated. Make the number of 22 tickets the same. LCM of 4 and 3 is 12.
1
12 =
32 Number of $22 tickets : $18 tickets = 3 : 2
|
$22 |
$18 |
Total |
Number |
9 u |
8 u |
|
Value |
$22 |
$18 |
|
Total value |
198 u |
144 u |
$2052 |
Total amount collected from the sale of the sold tickets
= 198 u + 144 u
= 342 u
1 u = 2052 ÷ 342 = 6
Number of $22-tickets left unsold
= 3 u
= 3 x 6
= 18
More amount to be collected if all the tickets were sold
= 18 x 22
= $396
Answer(s): $396