The tourist attraction tickets are priced at $25 and $19.  The number of $25-dollar tickets available is  1³₅ that of the number of $19-dollar tickets. 2 out of 5 of the $25-dollar tickets and all the $19-dollar tickets were sold. The ticket sales amounted to $7000. How much more would have been collected if all the tickets were sold?

	$25	$19
Comparing $25 and $19 tickets at first	8x5 = 40 u	5x5 = 25 u
Before	5x8 = 40 u
Change	- 2x8 = - 16 u	- 25 u
After	3x8 = 24 u	0 u

The number of 25 tickets at first is repeated.  Make the number of 25 tickets the same.  LCM of 5 and 8 is 40.

1³₅ = ⁸₅

Number of $25 tickets : $19 tickets = 8 : 5

	$25	$19	Total
Number	16 u	25 u
Value	$25	$19
Total value	400 u	475 u	$7000

Total amount collected from the sale of the sold tickets
= 400 u + 475 u
= 875 u

1 u = 7000 ÷ 875 = 8

Number of $25-tickets left unsold
= 24 u 
= 24 x 8
= 192

More amount to be collected if all the tickets were sold
= 192 x 25
= $4800

Answer(s): $4800