The bird park tickets are priced at $28 and $19. The number of $28-dollar tickets available is 1
13 that of the number of $19-dollar tickets. 3 out of 5 of the $28-dollar tickets and all the $19-dollar tickets were sold. The ticket sales amounted to $3105. How much more would have been collected if all the tickets were sold?
|
$28 |
$19 |
Comparing $28 and $19 tickets at first |
4x5 = 20 u |
3x5 = 15 u |
Before |
5x4 = 20 u |
|
Change |
- 3x4 = - 12 u |
- 15 u |
After |
2x4 = 8 u |
0 u |
The number of 28 tickets at first is repeated. Make the number of 28 tickets the same. LCM of 5 and 4 is 20.
1
13 =
43 Number of $28 tickets : $19 tickets = 4 : 3
|
$28 |
$19 |
Total |
Number |
12 u |
15 u |
|
Value |
$28 |
$19 |
|
Total value |
336 u |
285 u |
$3105 |
Total amount collected from the sale of the sold tickets
= 336 u + 285 u
= 621 u
1 u = 3105 ÷ 621 = 5
Number of $28-tickets left unsold
= 8 u
= 8 x 5
= 40
More amount to be collected if all the tickets were sold
= 40 x 28
= $1120
Answer(s): $1120