The zoo tickets are priced at $16 and $9. The number of $16-dollar tickets available is 1
56 that of the number of $9-dollar tickets. 3 out of 5 of the $16-dollar tickets and all the $9-dollar tickets were sold. The ticket sales amounted to $3990. How much more would have been collected if all the tickets were sold?
|
$16 |
$9 |
Comparing $16 and $9 tickets at first |
11x5 = 55 u |
6x5 = 30 u |
Before |
5x11 = 55 u |
|
Change |
- 3x11 = - 33 u |
- 30 u |
After |
2x11 = 22 u |
0 u |
The number of 16 tickets at first is repeated. Make the number of 16 tickets the same. LCM of 5 and 11 is 55.
1
56 =
116 Number of $16 tickets : $9 tickets = 11 : 6
|
$16 |
$9 |
Total |
Number |
33 u |
30 u |
|
Value |
$16 |
$9 |
|
Total value |
528 u |
270 u |
$3990 |
Total amount collected from the sale of the sold tickets
= 528 u + 270 u
= 798 u
1 u = 3990 ÷ 798 = 5
Number of $16-tickets left unsold
= 22 u
= 22 x 5
= 110
More amount to be collected if all the tickets were sold
= 110 x 16
= $1760
Answer(s): $1760