The safari park tickets are priced at $19 and $9. The number of $19-dollar tickets available is 1
56 that of the number of $9-dollar tickets. 3 out of 4 of the $19-dollar tickets and all the $9-dollar tickets were sold. The ticket sales amounted to $8430. How much more would have been collected if all the tickets were sold?
|
$19 |
$9 |
Comparing $19 and $9 tickets at first |
11x4 = 44 u |
6x4 = 24 u |
Before |
4x11 = 44 u |
|
Change |
- 3x11 = - 33 u |
- 24 u |
After |
1x11 = 11 u |
0 u |
The number of 19 tickets at first is repeated. Make the number of 19 tickets the same. LCM of 4 and 11 is 44.
1
56 =
116 Number of $19 tickets : $9 tickets = 11 : 6
|
$19 |
$9 |
Total |
Number |
33 u |
24 u |
|
Value |
$19 |
$9 |
|
Total value |
627 u |
216 u |
$8430 |
Total amount collected from the sale of the sold tickets
= 627 u + 216 u
= 843 u
1 u = 8430 ÷ 843 = 10
Number of $19-tickets left unsold
= 11 u
= 11 x 10
= 110
More amount to be collected if all the tickets were sold
= 110 x 19
= $2090
Answer(s): $2090