The tourist attraction tickets are priced at $10 and $8. The number of $10-dollar tickets available is 2
15 that of the number of $8-dollar tickets. 2 out of 5 of the $10-dollar tickets and all the $8-dollar tickets were sold. The ticket sales amounted to $4200. How much more would have been collected if all the tickets were sold?
|
$10 |
$8 |
Comparing $10 and $8 tickets at first |
11x5 = 55 u |
5x5 = 25 u |
Before |
5x11 = 55 u |
|
Change |
- 2x11 = - 22 u |
- 25 u |
After |
3x11 = 33 u |
0 u |
The number of 10 tickets at first is repeated. Make the number of 10 tickets the same. LCM of 5 and 11 is 55.
2
15 =
115 Number of $10 tickets : $8 tickets = 11 : 5
|
$10 |
$8 |
Total |
Number |
22 u |
25 u |
|
Value |
$10 |
$8 |
|
Total value |
220 u |
200 u |
$4200 |
Total amount collected from the sale of the sold tickets
= 220 u + 200 u
= 420 u
1 u = 4200 ÷ 420 = 10
Number of $10-tickets left unsold
= 33 u
= 33 x 10
= 330
More amount to be collected if all the tickets were sold
= 330 x 10
= $3300
Answer(s): $3300