The stadium tickets are priced at $28 and $20.  The number of $28-dollar tickets available is  2¹₅ that of the number of $20-dollar tickets. 3 out of 7 of the $28-dollar tickets and all the $20-dollar tickets were sold. The ticket sales amounted to $9744. How much more would have been collected if all the tickets were sold?

	$28	$20
Comparing $28 and $20 tickets at first	11x7 = 77 u	5x7 = 35 u
Before	7x11 = 77 u
Change	- 3x11 = - 33 u	- 35 u
After	4x11 = 44 u	0 u

The number of 28 tickets at first is repeated.  Make the number of 28 tickets the same.  LCM of 7 and 11 is 77.

2¹₅ = ¹¹₅

Number of $28 tickets : $20 tickets = 11 : 5

	$28	$20	Total
Number	33 u	35 u
Value	$28	$20
Total value	924 u	700 u	$9744

Total amount collected from the sale of the sold tickets
= 924 u + 700 u
= 1624 u

1 u = 9744 ÷ 1624 = 6

Number of $28-tickets left unsold
= 44 u 
= 44 x 6
= 264

More amount to be collected if all the tickets were sold
= 264 x 28
= $7392

Answer(s): $7392