The bird park tickets are priced at $20 and $15. The number of $20-dollar tickets available is 2
56 that of the number of $15-dollar tickets. 2 out of 5 of the $20-dollar tickets and all the $15-dollar tickets were sold. The ticket sales amounted to $10170. How much more would have been collected if all the tickets were sold?
|
$20 |
$15 |
Comparing $20 and $15 tickets at first |
17x5 = 85 u |
6x5 = 30 u |
Before |
5x17 = 85 u |
|
Change |
- 2x17 = - 34 u |
- 30 u |
After |
3x17 = 51 u |
0 u |
The number of 20 tickets at first is repeated. Make the number of 20 tickets the same. LCM of 5 and 17 is 85.
2
56 =
176 Number of $20 tickets : $15 tickets = 17 : 6
|
$20 |
$15 |
Total |
Number |
34 u |
30 u |
|
Value |
$20 |
$15 |
|
Total value |
680 u |
450 u |
$10170 |
Total amount collected from the sale of the sold tickets
= 680 u + 450 u
= 1130 u
1 u = 10170 ÷ 1130 = 9
Number of $20-tickets left unsold
= 51 u
= 51 x 9
= 459
More amount to be collected if all the tickets were sold
= 459 x 20
= $9180
Answer(s): $9180