The museum tickets are priced at $11 and $9. The number of $11-dollar tickets available is 2
15 that of the number of $9-dollar tickets. 3 out of 5 of the $11-dollar tickets and all the $9-dollar tickets were sold. The ticket sales amounted to $4116. How much more would have been collected if all the tickets were sold?
|
$11 |
$9 |
Comparing $11 and $9 tickets at first |
11x5 = 55 u |
5x5 = 25 u |
Before |
5x11 = 55 u |
|
Change |
- 3x11 = - 33 u |
- 25 u |
After |
2x11 = 22 u |
0 u |
The number of 11 tickets at first is repeated. Make the number of 11 tickets the same. LCM of 5 and 11 is 55.
2
15 =
115 Number of $11 tickets : $9 tickets = 11 : 5
|
$11 |
$9 |
Total |
Number |
33 u |
25 u |
|
Value |
$11 |
$9 |
|
Total value |
363 u |
225 u |
$4116 |
Total amount collected from the sale of the sold tickets
= 363 u + 225 u
= 588 u
1 u = 4116 ÷ 588 = 7
Number of $11-tickets left unsold
= 22 u
= 22 x 7
= 154
More amount to be collected if all the tickets were sold
= 154 x 11
= $1694
Answer(s): $1694