The museum tickets are priced at $9 and $6. The number of $9-dollar tickets available is 1
13 that of the number of $6-dollar tickets. 3 out of 7 of the $9-dollar tickets and all the $6-dollar tickets were sold. The ticket sales amounted to $936. How much more would have been collected if all the tickets were sold?
|
$9 |
$6 |
Comparing $9 and $6 tickets at first |
4x7 = 28 u |
3x7 = 21 u |
Before |
7x4 = 28 u |
|
Change |
- 3x4 = - 12 u |
- 21 u |
After |
4x4 = 16 u |
0 u |
The number of 9 tickets at first is repeated. Make the number of 9 tickets the same. LCM of 7 and 4 is 28.
1
13 =
43 Number of $9 tickets : $6 tickets = 4 : 3
|
$9 |
$6 |
Total |
Number |
12 u |
21 u |
|
Value |
$9 |
$6 |
|
Total value |
108 u |
126 u |
$936 |
Total amount collected from the sale of the sold tickets
= 108 u + 126 u
= 234 u
1 u = 936 ÷ 234 = 4
Number of $9-tickets left unsold
= 16 u
= 16 x 4
= 64
More amount to be collected if all the tickets were sold
= 64 x 9
= $576
Answer(s): $576