The tourist attraction tickets are priced at $22 and $12. The number of $22-dollar tickets available is 2
12 that of the number of $12-dollar tickets. 2 out of 3 of the $22-dollar tickets and all the $12-dollar tickets were sold. The ticket sales amounted to $1168. How much more would have been collected if all the tickets were sold?
|
$22 |
$12 |
Comparing $22 and $12 tickets at first |
5x3 = 15 u |
2x3 = 6 u |
Before |
3x5 = 15 u |
|
Change |
- 2x5 = - 10 u |
- 6 u |
After |
1x5 = 5 u |
0 u |
The number of 22 tickets at first is repeated. Make the number of 22 tickets the same. LCM of 3 and 5 is 15.
2
12 =
52 Number of $22 tickets : $12 tickets = 5 : 2
|
$22 |
$12 |
Total |
Number |
10 u |
6 u |
|
Value |
$22 |
$12 |
|
Total value |
220 u |
72 u |
$1168 |
Total amount collected from the sale of the sold tickets
= 220 u + 72 u
= 292 u
1 u = 1168 ÷ 292 = 4
Number of $22-tickets left unsold
= 5 u
= 5 x 4
= 20
More amount to be collected if all the tickets were sold
= 20 x 22
= $440
Answer(s): $440