The park tickets are priced at $20 and $11. The number of $20-dollar tickets available is 2
56 that of the number of $11-dollar tickets. 3 out of 4 of the $20-dollar tickets and all the $11-dollar tickets were sold. The ticket sales amounted to $6420. How much more would have been collected if all the tickets were sold?
|
$20 |
$11 |
Comparing $20 and $11 tickets at first |
17x4 = 68 u |
6x4 = 24 u |
Before |
4x17 = 68 u |
|
Change |
- 3x17 = - 51 u |
- 24 u |
After |
1x17 = 17 u |
0 u |
The number of 20 tickets at first is repeated. Make the number of 20 tickets the same. LCM of 4 and 17 is 68.
2
56 =
176 Number of $20 tickets : $11 tickets = 17 : 6
|
$20 |
$11 |
Total |
Number |
51 u |
24 u |
|
Value |
$20 |
$11 |
|
Total value |
1020 u |
264 u |
$6420 |
Total amount collected from the sale of the sold tickets
= 1020 u + 264 u
= 1284 u
1 u = 6420 ÷ 1284 = 5
Number of $20-tickets left unsold
= 17 u
= 17 x 5
= 85
More amount to be collected if all the tickets were sold
= 85 x 20
= $1700
Answer(s): $1700