The museum tickets are priced at $20 and $14. The number of $20-dollar tickets available is 1
12 that of the number of $14-dollar tickets. 3 out of 4 of the $20-dollar tickets and all the $14-dollar tickets were sold. The ticket sales amounted to $3504. How much more would have been collected if all the tickets were sold?
|
$20 |
$14 |
Comparing $20 and $14 tickets at first |
3x4 = 12 u |
2x4 = 8 u |
Before |
4x3 = 12 u |
|
Change |
- 3x3 = - 9 u |
- 8 u |
After |
1x3 = 3 u |
0 u |
The number of 20 tickets at first is repeated. Make the number of 20 tickets the same. LCM of 4 and 3 is 12.
1
12 =
32 Number of $20 tickets : $14 tickets = 3 : 2
|
$20 |
$14 |
Total |
Number |
9 u |
8 u |
|
Value |
$20 |
$14 |
|
Total value |
180 u |
112 u |
$3504 |
Total amount collected from the sale of the sold tickets
= 180 u + 112 u
= 292 u
1 u = 3504 ÷ 292 = 12
Number of $20-tickets left unsold
= 3 u
= 3 x 12
= 36
More amount to be collected if all the tickets were sold
= 36 x 20
= $720
Answer(s): $720