The tourist attraction tickets are priced at $19 and $16. The number of $19-dollar tickets available is 1
35 that of the number of $16-dollar tickets. 2 out of 3 of the $19-dollar tickets and all the $16-dollar tickets were sold. The ticket sales amounted to $5440. How much more would have been collected if all the tickets were sold?
|
$19 |
$16 |
Comparing $19 and $16 tickets at first |
8x3 = 24 u |
5x3 = 15 u |
Before |
3x8 = 24 u |
|
Change |
- 2x8 = - 16 u |
- 15 u |
After |
1x8 = 8 u |
0 u |
The number of 19 tickets at first is repeated. Make the number of 19 tickets the same. LCM of 3 and 8 is 24.
1
35 =
85 Number of $19 tickets : $16 tickets = 8 : 5
|
$19 |
$16 |
Total |
Number |
16 u |
15 u |
|
Value |
$19 |
$16 |
|
Total value |
304 u |
240 u |
$5440 |
Total amount collected from the sale of the sold tickets
= 304 u + 240 u
= 544 u
1 u = 5440 ÷ 544 = 10
Number of $19-tickets left unsold
= 8 u
= 8 x 10
= 80
More amount to be collected if all the tickets were sold
= 80 x 19
= $1520
Answer(s): $1520