The zoo tickets are priced at $8 and $6. The number of $8-dollar tickets available is 2
15 that of the number of $6-dollar tickets. 3 out of 4 of the $8-dollar tickets and all the $6-dollar tickets were sold. The ticket sales amounted to $2304. How much more would have been collected if all the tickets were sold?
|
$8 |
$6 |
Comparing $8 and $6 tickets at first |
11x4 = 44 u |
5x4 = 20 u |
Before |
4x11 = 44 u |
|
Change |
- 3x11 = - 33 u |
- 20 u |
After |
1x11 = 11 u |
0 u |
The number of 8 tickets at first is repeated. Make the number of 8 tickets the same. LCM of 4 and 11 is 44.
2
15 =
115 Number of $8 tickets : $6 tickets = 11 : 5
|
$8 |
$6 |
Total |
Number |
33 u |
20 u |
|
Value |
$8 |
$6 |
|
Total value |
264 u |
120 u |
$2304 |
Total amount collected from the sale of the sold tickets
= 264 u + 120 u
= 384 u
1 u = 2304 ÷ 384 = 6
Number of $8-tickets left unsold
= 11 u
= 11 x 6
= 66
More amount to be collected if all the tickets were sold
= 66 x 8
= $528
Answer(s): $528