The bird park tickets are priced at $26 and $20. The number of $26-dollar tickets available is 1
45 that of the number of $20-dollar tickets. 2 out of 3 of the $26-dollar tickets and all the $20-dollar tickets were sold. The ticket sales amounted to $2560. How much more would have been collected if all the tickets were sold?
|
$26 |
$20 |
Comparing $26 and $20 tickets at first |
9x1 = 9 u |
5x1 = 5 u |
Before |
3x3 = 9 u |
|
Change |
- 2x3 = - 6 u |
- 5 u |
After |
1x3 = 3 u |
0 u |
The number of 26 tickets at first is repeated. Make the number of 26 tickets the same. LCM of 3 and 9 is 9.
1
45 =
95 Number of $26 tickets : $20 tickets = 9 : 5
|
$26 |
$20 |
Total |
Number |
6 u |
5 u |
|
Value |
$26 |
$20 |
|
Total value |
156 u |
100 u |
$2560 |
Total amount collected from the sale of the sold tickets
= 156 u + 100 u
= 256 u
1 u = 2560 ÷ 256 = 10
Number of $26-tickets left unsold
= 3 u
= 3 x 10
= 30
More amount to be collected if all the tickets were sold
= 30 x 26
= $780
Answer(s): $780