The safari park tickets are priced at $13 and $5. The number of $13-dollar tickets available is 1
45 that of the number of $5-dollar tickets. 3 out of 5 of the $13-dollar tickets and all the $5-dollar tickets were sold. The ticket sales amounted to $5712. How much more would have been collected if all the tickets were sold?
|
$13 |
$5 |
Comparing $13 and $5 tickets at first |
9x5 = 45 u |
5x5 = 25 u |
Before |
5x9 = 45 u |
|
Change |
- 3x9 = - 27 u |
- 25 u |
After |
2x9 = 18 u |
0 u |
The number of 13 tickets at first is repeated. Make the number of 13 tickets the same. LCM of 5 and 9 is 45.
1
45 =
95 Number of $13 tickets : $5 tickets = 9 : 5
|
$13 |
$5 |
Total |
Number |
27 u |
25 u |
|
Value |
$13 |
$5 |
|
Total value |
351 u |
125 u |
$5712 |
Total amount collected from the sale of the sold tickets
= 351 u + 125 u
= 476 u
1 u = 5712 ÷ 476 = 12
Number of $13-tickets left unsold
= 18 u
= 18 x 12
= 216
More amount to be collected if all the tickets were sold
= 216 x 13
= $2808
Answer(s): $2808