The park tickets are priced at $12 and $5. The number of $12-dollar tickets available is 1
13 that of the number of $5-dollar tickets. 3 out of 5 of the $12-dollar tickets and all the $5-dollar tickets were sold. The ticket sales amounted to $2628. How much more would have been collected if all the tickets were sold?
|
$12 |
$5 |
Comparing $12 and $5 tickets at first |
4x5 = 20 u |
3x5 = 15 u |
Before |
5x4 = 20 u |
|
Change |
- 3x4 = - 12 u |
- 15 u |
After |
2x4 = 8 u |
0 u |
The number of 12 tickets at first is repeated. Make the number of 12 tickets the same. LCM of 5 and 4 is 20.
1
13 =
43 Number of $12 tickets : $5 tickets = 4 : 3
|
$12 |
$5 |
Total |
Number |
12 u |
15 u |
|
Value |
$12 |
$5 |
|
Total value |
144 u |
75 u |
$2628 |
Total amount collected from the sale of the sold tickets
= 144 u + 75 u
= 219 u
1 u = 2628 ÷ 219 = 12
Number of $12-tickets left unsold
= 8 u
= 8 x 12
= 96
More amount to be collected if all the tickets were sold
= 96 x 12
= $1152
Answer(s): $1152