The safari park tickets are priced at $22 and $14. The number of $22-dollar tickets available is 2
23 that of the number of $14-dollar tickets. 2 out of 3 of the $22-dollar tickets and all the $14-dollar tickets were sold. The ticket sales amounted to $4302. How much more would have been collected if all the tickets were sold?
|
$22 |
$14 |
Comparing $22 and $14 tickets at first |
8x3 = 24 u |
3x3 = 9 u |
Before |
3x8 = 24 u |
|
Change |
- 2x8 = - 16 u |
- 9 u |
After |
1x8 = 8 u |
0 u |
The number of 22 tickets at first is repeated. Make the number of 22 tickets the same. LCM of 3 and 8 is 24.
2
23 =
83 Number of $22 tickets : $14 tickets = 8 : 3
|
$22 |
$14 |
Total |
Number |
16 u |
9 u |
|
Value |
$22 |
$14 |
|
Total value |
352 u |
126 u |
$4302 |
Total amount collected from the sale of the sold tickets
= 352 u + 126 u
= 478 u
1 u = 4302 ÷ 478 = 9
Number of $22-tickets left unsold
= 8 u
= 8 x 9
= 72
More amount to be collected if all the tickets were sold
= 72 x 22
= $1584
Answer(s): $1584