The tourist attraction tickets are priced at $15 and $5.  The number of $15-dollar tickets available is  2¹₂ that of the number of $5-dollar tickets. 3 out of 7 of the $15-dollar tickets and all the $5-dollar tickets were sold. The ticket sales amounted to $3245. How much more would have been collected if all the tickets were sold?

	$15	$5
Comparing $15 and $5 tickets at first	5x7 = 35 u	2x7 = 14 u
Before	7x5 = 35 u
Change	- 3x5 = - 15 u	- 14 u
After	4x5 = 20 u	0 u

The number of 15 tickets at first is repeated.  Make the number of 15 tickets the same.  LCM of 7 and 5 is 35.

2¹₂ = ⁵₂

Number of $15 tickets : $5 tickets = 5 : 2

	$15	$5	Total
Number	15 u	14 u
Value	$15	$5
Total value	225 u	70 u	$3245

Total amount collected from the sale of the sold tickets
= 225 u + 70 u
= 295 u

1 u = 3245 ÷ 295 = 11

Number of $15-tickets left unsold
= 20 u 
= 20 x 11
= 220

More amount to be collected if all the tickets were sold
= 220 x 15
= $3300

Answer(s): $3300