The safari park tickets are priced at $10 and $6.  The number of $10-dollar tickets available is  1¹₂ that of the number of $6-dollar tickets. 3 out of 5 of the $10-dollar tickets and all the $6-dollar tickets were sold. The ticket sales amounted to $1200. How much more would have been collected if all the tickets were sold?

	$10	$6
Comparing $10 and $6 tickets at first	3x5 = 15 u	2x5 = 10 u
Before	5x3 = 15 u
Change	- 3x3 = - 9 u	- 10 u
After	2x3 = 6 u	0 u

The number of 10 tickets at first is repeated.  Make the number of 10 tickets the same.  LCM of 5 and 3 is 15.

1¹₂ = ³₂

Number of $10 tickets : $6 tickets = 3 : 2

	$10	$6	Total
Number	9 u	10 u
Value	$10	$6
Total value	90 u	60 u	$1200

Total amount collected from the sale of the sold tickets
= 90 u + 60 u
= 150 u

1 u = 1200 ÷ 150 = 8

Number of $10-tickets left unsold
= 6 u 
= 6 x 8
= 48

More amount to be collected if all the tickets were sold
= 48 x 10
= $480

Answer(s): $480