The safari park tickets are priced at $18 and $11. The number of $18-dollar tickets available is 2
56 that of the number of $11-dollar tickets. 2 out of 3 of the $18-dollar tickets and all the $11-dollar tickets were sold. The ticket sales amounted to $9720. How much more would have been collected if all the tickets were sold?
|
$18 |
$11 |
Comparing $18 and $11 tickets at first |
17x3 = 51 u |
6x3 = 18 u |
Before |
3x17 = 51 u |
|
Change |
- 2x17 = - 34 u |
- 18 u |
After |
1x17 = 17 u |
0 u |
The number of 18 tickets at first is repeated. Make the number of 18 tickets the same. LCM of 3 and 17 is 51.
2
56 =
176 Number of $18 tickets : $11 tickets = 17 : 6
|
$18 |
$11 |
Total |
Number |
34 u |
18 u |
|
Value |
$18 |
$11 |
|
Total value |
612 u |
198 u |
$9720 |
Total amount collected from the sale of the sold tickets
= 612 u + 198 u
= 810 u
1 u = 9720 ÷ 810 = 12
Number of $18-tickets left unsold
= 17 u
= 17 x 12
= 204
More amount to be collected if all the tickets were sold
= 204 x 18
= $3672
Answer(s): $3672