The park tickets are priced at $21 and $16. The number of $21-dollar tickets available is 2
15 that of the number of $16-dollar tickets. 3 out of 7 of the $21-dollar tickets and all the $16-dollar tickets were sold. The ticket sales amounted to $12530. How much more would have been collected if all the tickets were sold?
|
$21 |
$16 |
Comparing $21 and $16 tickets at first |
11x7 = 77 u |
5x7 = 35 u |
Before |
7x11 = 77 u |
|
Change |
- 3x11 = - 33 u |
- 35 u |
After |
4x11 = 44 u |
0 u |
The number of 21 tickets at first is repeated. Make the number of 21 tickets the same. LCM of 7 and 11 is 77.
2
15 =
115 Number of $21 tickets : $16 tickets = 11 : 5
|
$21 |
$16 |
Total |
Number |
33 u |
35 u |
|
Value |
$21 |
$16 |
|
Total value |
693 u |
560 u |
$12530 |
Total amount collected from the sale of the sold tickets
= 693 u + 560 u
= 1253 u
1 u = 12530 ÷ 1253 = 10
Number of $21-tickets left unsold
= 44 u
= 44 x 10
= 440
More amount to be collected if all the tickets were sold
= 440 x 21
= $9240
Answer(s): $9240