The tourist attraction tickets are priced at $14 and $8. The number of $14-dollar tickets available is 2
12 that of the number of $8-dollar tickets. 3 out of 4 of the $14-dollar tickets and all the $8-dollar tickets were sold. The ticket sales amounted to $548. How much more would have been collected if all the tickets were sold?
|
$14 |
$8 |
Comparing $14 and $8 tickets at first |
5x4 = 20 u |
2x4 = 8 u |
Before |
4x5 = 20 u |
|
Change |
- 3x5 = - 15 u |
- 8 u |
After |
1x5 = 5 u |
0 u |
The number of 14 tickets at first is repeated. Make the number of 14 tickets the same. LCM of 4 and 5 is 20.
2
12 =
52 Number of $14 tickets : $8 tickets = 5 : 2
|
$14 |
$8 |
Total |
Number |
15 u |
8 u |
|
Value |
$14 |
$8 |
|
Total value |
210 u |
64 u |
$548 |
Total amount collected from the sale of the sold tickets
= 210 u + 64 u
= 274 u
1 u = 548 ÷ 274 = 2
Number of $14-tickets left unsold
= 5 u
= 5 x 2
= 10
More amount to be collected if all the tickets were sold
= 10 x 14
= $140
Answer(s): $140