The bird park tickets are priced at $16 and $6. The number of $16-dollar tickets available is 1
56 that of the number of $6-dollar tickets. 2 out of 5 of the $16-dollar tickets and all the $6-dollar tickets were sold. The ticket sales amounted to $3724. How much more would have been collected if all the tickets were sold?
|
$16 |
$6 |
Comparing $16 and $6 tickets at first |
11x5 = 55 u |
6x5 = 30 u |
Before |
5x11 = 55 u |
|
Change |
- 2x11 = - 22 u |
- 30 u |
After |
3x11 = 33 u |
0 u |
The number of 16 tickets at first is repeated. Make the number of 16 tickets the same. LCM of 5 and 11 is 55.
1
56 =
116 Number of $16 tickets : $6 tickets = 11 : 6
|
$16 |
$6 |
Total |
Number |
22 u |
30 u |
|
Value |
$16 |
$6 |
|
Total value |
352 u |
180 u |
$3724 |
Total amount collected from the sale of the sold tickets
= 352 u + 180 u
= 532 u
1 u = 3724 ÷ 532 = 7
Number of $16-tickets left unsold
= 33 u
= 33 x 7
= 231
More amount to be collected if all the tickets were sold
= 231 x 16
= $3696
Answer(s): $3696