Shiyun spent
34 of her money on 12 notebooks and 8 markers. The cost of each marker is 3 times the cost of each notebook. She bought some more notebooks with
34 of her remaining money. How many notebooks did Shiyun buy altogether?
12 notebooks + 8 markers |
Remaining amount |
Total amount |
3 p = 36 u |
1 p = 12 u |
4 p |
12 notebooks |
8 markers |
More notebooks |
Left |
|
|
|
3 |
1 |
|
12 u |
24 u |
9 u |
|
|
Cost of 1 notebook = 1 u
Cost of 1 marker = 3 u
Cost of 12 notebooks = 12 x 1 u = 12 u
Cost of 8 markers = 8 x 3 u = 24 u
Cost of 12 notebooks + 8 markers
= 12 u + 24 u
= 36 u
3 p = 36 u
1 p = 36 u ÷ 3 = 12 u
Amount of remaining money that Shiyun spent on buying more notebooks
=
34 x 12 u
= 9 u
Number of notebooks that Shiyun bought with
34 of her remaining money
= 9 u ÷ 1 u
= 9
Total number of notebooks that Shiyun bought
= 12 + 9
= 21
Answer(s): 21