Shannon spent
23 of her money on 15 pencils and 9 markers. The cost of each marker is 3 times the cost of each pencil. She bought some more pencils with
67 of her remaining money. How many pencils did Shannon buy altogether?
| 15 pencils + 9 markers |
Remaining
amount |
Total
amount |
| 2 p = 42 u |
1 p = 21 u |
3 p |
15
pencils |
9
markers |
More pencils |
Left |
|
| |
|
6 |
1 |
|
| 15 u |
27 u |
18 u |
|
|
Cost of 1 pencil = 1 u
Cost of 1 marker = 3 u
Cost of 15 pencils = 15 x 1 u = 15 u
Cost of 9 markers = 9 x 3 u = 27 u
Cost of 15 pencils + 9 markers
= 15 u + 27 u
= 42 u
2 p = 42 u
1 p = 42 u ÷ 2 = 21 u
Amount of remaining money that Shannon spent on buying more pencils
=
67 x 21 u
= 18 u
Number of pencils that Shannon bought with
67 of her remaining money
= 18 u ÷ 1 u
= 18
Total number of pencils that Shannon bought
= 15 + 18
= 33
Answer(s): 33
