Linda spent
45 of her money on 10 pencils and 7 notebooks. The cost of each notebook is 2 times the cost of each pencil. She bought some more pencils with
23 of her remaining money. How many pencils did Linda buy altogether?
| 10 pencils + 7 notebooks |
Remaining
amount |
Total
amount |
| 4 p = 24 u |
1 p = 6 u |
5 p |
10
pencils |
7
notebooks |
More pencils |
Left |
|
| |
|
2 |
1 |
|
| 10 u |
14 u |
4 u |
|
|
Cost of 1 pencil = 1 u
Cost of 1 notebook = 2 u
Cost of 10 pencils = 10 x 1 u = 10 u
Cost of 7 notebooks = 7 x 2 u = 14 u
Cost of 10 pencils + 7 notebooks
= 10 u + 14 u
= 24 u
4 p = 24 u
1 p = 24 u ÷ 4 = 6 u
Amount of remaining money that Linda spent on buying more pencils
=
23 x 6 u
= 4 u
Number of pencils that Linda bought with
23 of her remaining money
= 4 u ÷ 1 u
= 4
Total number of pencils that Linda bought
= 10 + 4
= 14
Answer(s): 14
