Linda spent
34 of her money on 12 pencils and 6 markers. The cost of each marker is 2 times the cost of each pencil. She bought some more pencils with
34 of her remaining money. How many pencils did Linda buy altogether?
| 12 pencils + 6 markers |
Remaining
amount |
Total
amount |
| 3 p = 24 u |
1 p = 8 u |
4 p |
12
pencils |
6
markers |
More pencils |
Left |
|
| |
|
3 |
1 |
|
| 12 u |
12 u |
6 u |
|
|
Cost of 1 pencil = 1 u
Cost of 1 marker = 2 u
Cost of 12 pencils = 12 x 1 u = 12 u
Cost of 6 markers = 6 x 2 u = 12 u
Cost of 12 pencils + 6 markers
= 12 u + 12 u
= 24 u
3 p = 24 u
1 p = 24 u ÷ 3 = 8 u
Amount of remaining money that Linda spent on buying more pencils
=
34 x 8 u
= 6 u
Number of pencils that Linda bought with
34 of her remaining money
= 6 u ÷ 1 u
= 6
Total number of pencils that Linda bought
= 12 + 6
= 18
Answer(s): 18
