Xuan spent
45 of her money on 10 markers and 5 pencils. The cost of each pencil is 2 times the cost of each marker. She bought some more markers with
45 of her remaining money. How many markers did Xuan buy altogether?
| 10 markers + 5 pencils |
Remaining
amount |
Total
amount |
| 4 p = 20 u |
1 p = 5 u |
5 p |
10
markers |
5
pencils |
More markers |
Left |
|
| |
|
4 |
1 |
|
| 10 u |
10 u |
4 u |
|
|
Cost of 1 marker = 1 u
Cost of 1 pencil = 2 u
Cost of 10 markers = 10 x 1 u = 10 u
Cost of 5 pencils = 5 x 2 u = 10 u
Cost of 10 markers + 5 pencils
= 10 u + 10 u
= 20 u
4 p = 20 u
1 p = 20 u ÷ 4 = 5 u
Amount of remaining money that Xuan spent on buying more markers
=
45 x 5 u
= 4 u
Number of markers that Xuan bought with
45 of her remaining money
= 4 u ÷ 1 u
= 4
Total number of markers that Xuan bought
= 10 + 4
= 14
Answer(s): 14
