In a pouch of notes, the number of $10, $20 and $50 are in ratio of 2 : 1 : 1.
12 of the $10-notes is taken out and another 14 $20-notes are added. The remaining notes are worth $1160. Find the difference between the value of $50-notes and $10-notes in the end.
| |
$10 |
$20 |
$50 |
| Before |
2 u |
1 u |
1 u |
| Change |
- 1 u |
+ 14 |
|
| After |
1 u |
1 u + 14 |
1 u |
| |
$10 |
$20 |
$50 |
Total |
| Number |
1 u |
1 u + 14 |
1 u |
|
| Value |
10 |
20 |
50 |
|
| Total value |
10 u |
20 u + 280 |
50 u |
1160 |
Total value of the notes
= 10 u + 20 u + 280 + 50 u
= 80 u + 280
80 u + 280 = 1160
80 u = 1160 - 280
80 u = 880
1 u = 880 ÷ 80 = 11
Difference between the value of $50-notes and $10-notes in the end
= 50 u - 10 u
= 40 u
= 40 x 11
= $440
Answer(s): $440
