In a bag of notes, the number of $2, $10 and $100 are in ratio of 7 : 2 : 2.
47 of the $2-notes is taken out and another 10 $10-notes are added. The remaining notes are worth $2360. Find the difference between the value of $100-notes and $2-notes in the end.
|
$2 |
$10 |
$100 |
Before |
7 u |
2 u |
2 u |
Change |
- 4 u |
+ 10 |
|
After |
3 u |
2 u + 10 |
2 u |
|
$2 |
$10 |
$100 |
Total |
Number |
3 u |
2 u + 10 |
2 u |
|
Value |
2 |
10 |
100 |
|
Total value |
6 u |
20 u + 100 |
200 u |
2360 |
Total value of the notes
= 6 u + 20 u + 100 + 200 u
= 226 u + 100
226 u + 100 = 2360
226 u = 2360 - 100
226 u = 2260
1 u = 2260 ÷ 226 = 10
Difference between the value of $100-notes and $2-notes in the end
= 200 u - 6 u
= 194 u
= 194 x 10
= $1940
Answer(s): $1940